Examples of using Non-empty in English and their translations into Portuguese
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Colloquial
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Official
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Medicine
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Ecclesiastic
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Ecclesiastic
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Computer
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Official/political
For example, suppose that"X" is the set of all non-empty subsets of the real numbers.
why then opt for the hypothesis of the non-empty sepulcher?
The data and journal providers need to be on different partitions when journaling an existing(non-empty) partition.
you can set all non-empty pages as print area,
However not all authors insist on the underlying set of a semigroup being non-empty.
it will extend the selection to the first non-empty cell below the selected cell as following screenshot shown.
does any non-empty subset of them add up to zero?
In mathematics, a well-order relation(or well-ordering) on a set"S" is a total order on"S" with the property that every non-empty subset of"S" has a least element in this ordering.
For example, after having established that the set"X" contains only non-empty sets, a mathematician might have said"let"F(s)" be one of the members of"s" for all"s" in"X.
Executes block if expression is true(non-zero number or non-empty string.) Old Close with@endif New if val== true then// do op elseif cond// second chance else// cond failed endif.
There is a set"A" such that for all functions"f"(on the set of non-empty subsets of"A"), there is a"B" such that"f"("B") does not lie in"B.
formula_10If"A" is a finite non-empty set, one can replace the unweighted mean or average: formula_11by the weighted mean or weighted average: formula_12In this case only the"relative" weights are relevant.
These 4,719 keywords were used in 6,466 valid cataloging records non-empty for published items a mean of 2.55 keywords per article:
while the body of the machine is just 6,329 non-empty cells(within a rectangle of size 97x170),
Given any set X of pairwise disjoint non-empty sets, there exists at least one set C that contains exactly one element in common with each of the sets in X. This guarantees for any partition of a set X the existence of a subset C of X containing exactly one element from each part of the partition.
with\phi(x) non-empty, closed and convex for all x belongs to x,
then eR e, and for each non-empty word w x1…xn over some alphabet,
equivalently, every non-empty subset of the set has a least element.
his failure to retain the"theorem that an arbitrary non-empty set M of real numbers having an upper bound has a least upper bound cf. also Weyl 1919.
there is a filter"F" on"P" such that"F"∩"d" is non-empty for every"d" in"D.